2. Electric Potential and Capacitance
hard

तीन संकेन्द्री धातु कोष $A, B$ तथा $C$ जिनकी त्रिज्यायें क्रमशः $a$, $b$ तथा $c(a< b< c)$ हैं, का पृष्ठ-आवेश-घनत्व क्रमश : $+\sigma$ $-\sigma$ तथा $+\sigma$ है। कोष $B$ का विभव होगा

A

$\frac{\sigma}{\epsilon_0} \left[ {\frac{a^2-b^2}{b}+c} \right ]$

B

$\frac{\sigma}{\epsilon_0} \left[ {\frac{b^2-c^2}{b}+a} \right ]$

C

$\frac{\sigma}{\epsilon_0} \left[ {\frac{b^2-c^2}{c}+a} \right ]$

D

$\frac{\sigma}{\epsilon_0} \left[ {\frac{a^2-b^2}{a}+c} \right ]$

(JEE MAIN-2018)

Solution

Potential outside the shell, $V_{outside}$ $=\frac{\mathrm{KQ}}{\mathrm{r}}$

where $\mathrm{r}$ is distance of point from the centre of shel Potential inside the shell, $V_{\text {inside }}=\frac{K Q}{R}$

where $'R"$ is radius of the shell

$\mathrm{V}_{\mathrm{B}}=\frac{\mathrm{Kq}_{\mathrm{A}}}{\mathrm{r}_{\mathrm{b}}}+\frac{\mathrm{Kq}_{\mathrm{B}}}{\mathrm{r}_{\mathrm{b}}}+\frac{\mathrm{Kq}_{\mathrm{C}}}{\mathrm{r}_{\mathrm{c}}}$

$\mathrm{V}_{\mathrm{B}}=\frac{1}{4 \pi \epsilon_{0}}\left[\frac{\sigma 4 \pi \mathrm{a}^{2}}{\mathrm{b}}-\frac{\sigma 4 \pi \mathrm{b}^{2}}{\mathrm{b}}+\frac{\sigma 4 \pi \mathrm{c}^{2}}{\mathrm{c}}\right]$

$V_{B}=\frac{\sigma}{\epsilon_{0}}\left[\frac{a^{2}-b^{2}}{b}+c\right]$

Standard 12
Physics

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