ત્રણ સમકેન્દ્રિયો ધાતુ કવચો A,B અને C ની અનુક | vedclass

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Question

Potential outside the shell, $V_{outside}$ $=\frac{\mathrm{KQ}}{\mathrm{r}}$

where $\mathrm{r}$ is distance of point from the centre of shel Potent

Vedclass · Accepted Answer

$\frac{\sigma}{\epsilon_0} \left[ {\frac{a^2-b^2}{b}+c} \right ]$

Vedclass · Answer

Potential outside the shell, $V_{outside}$ $=\frac{\mathrm{KQ}}{\mathrm{r}}$

where $\mathrm{r}$ is distance of point from the centre of shel Potential inside the shell, $V_{	ext {inside }}=\frac{K Q}{R}$ 

where $'R"$ is radius of the shell

$\mathrm{V}_{\mathrm{B}}=\frac{\mathrm{Kq}_{\mathrm{A}}}{\mathrm{r}_{\mathrm{b}}}+\frac{\mathrm{Kq}_{\mathrm{B}}}{\mathrm{r}_{\mathrm{b}}}+\frac{\mathrm{Kq}_{\mathrm{C}}}{\mathrm{r}_{\mathrm{c}}}$

$\mathrm{V}_{\mathrm{B}}=\frac{1}{4 \pi \epsilon_{0}}\left[\frac{\sigma 4 \pi \mathrm{a}^{2}}{\mathrm{b}}-\frac{\sigma 4 \pi \mathrm{b}^{2}}{\mathrm{b}}+\frac{\sigma 4 \pi \mathrm{c}^{2}}{\mathrm{c}}ight]$

$V_{B}=\frac{\sigma}{\epsilon_{0}}\left[\frac{a^{2}-b^{2}}{b}+cight]$

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