Three identical balls are projected with the | vedclass

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Question

$30^{\circ}+60^{\circ}=90^{\circ}$

$	herefore \mathrm{R}_{1}=\mathrm{R}_{3}$

and we get maximum range

for $	heta=45^{\circ}$

so $\mathrm

Vedclass · Accepted Answer

$R_1 = R_3 < R_2$

Vedclass · Answer

$30^{\circ}+60^{\circ}=90^{\circ}$

$	herefore \mathrm{R}_{1}=\mathrm{R}_{3}$

and we get maximum range

for $	heta=45^{\circ}$

so $\mathrm{R}_{2}$ will be maximum hence $\mathrm{R}_{1}=\mathrm{R}_{3}<\mathrm{R}_{2}$

Three identical balls are projected with the same speed at angle $30^o, 45^o$ and $60^o$. Their ranges are $R_1 R_2$ and $R_3$ respectively. Then

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