Two particles are projected from the same poi | vedclass

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Question

$\begin{array}{l} For\,same\,range\,angle\,of\,projection\,will\ be\,	heta \,will\,be\,	heta \,\& \,90 - 	heta \ R\,\, = \,\frac{{{u^2}2\sin

Vedclass · Accepted Answer

$R^2 = 16 h_1h_2$

Vedclass · Answer

$\begin{array}{l} For\,same\,range\,angle\,of\,projection\,will\ be\,	heta \,will\,be\,	heta \,\& \,90 - 	heta \ R\,\, = \,\frac{{{u^2}2\sin 	heta \cos 	heta }}{g}\ {h_1} = \frac{{{u^2}{{\sin }^2}	heta }}{g}\ {h_2} = \frac{{{u^2}\sin {\,^2}\left( {90 - 	heta } ight)}}{g}\ \frac{{{R^2}}}{{{h_1}{h_2}}} = 16 \end{array}$

Two particles are projected from the same point with the same speed $u$ such that they have the same range $R$, but different maximum heights, $h_1$ and $h_2$. Which of the following is correct ?

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