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7.Profit and Loss
medium
Three successive discounts of $10 \%, 12 \%$ and $15 \%$ will amount to a single discount of in $\%$?
A
$36.28$
B
$32.68$
C
$34.68$
D
$37$
Solution
Three successful discount equivalent to
$\left[x+y+z-\frac{x y+y z+z x}{100}+\frac{x y z}{(100)^{2}}\right] \%$
(where $x=10 \%, y=12 \%, z=15 \%)$
$\left[10+12+15-\frac{10 \times 12+12 \times 15+15 \times 10}{100}+\frac{10 \times 12 \times 15}{(100)^{2}}\right] \%$
$37-4.50+0.18=32.68 \%$
Standard 13
Quantitative Aptitude