Triangle formed by lines 3x + y + 4 = 0 , 3x + 4y -15 = 0 and 24x -7y = 3 is a/an

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9.Straight Line

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Triangle formed by the lines $3x + y + 4 = 0$ , $3x + 4y -15 = 0$ and $24x -7y = 3$ is a/an

A

equilateral triangle

B

isosceles triangle

C

acute angle triangle

D

scalene triangle

Solution

$\frac{24}{7}>-\frac{3}{4}>-3$

$\tan A=\frac{\frac{24}{7}+\frac{3}{4}}{1-\frac{24}{7} \cdot \frac{3}{4}}=-\frac{117}{51},$

$\tan B=\frac{-\frac{3}{4}+3}{1+\frac{9}{4}}=\frac{9}{13}$

$\tan C=\frac{-3-\frac{24}{7}}{1-3 \cdot \frac{24}{7}}=\frac{45}{65}=\frac{9}{13}$

Standard 11

Mathematics

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