Two bodies with kinetic energies in the ratio of $4 : 1$ are moving with equal linear momentum. The ratio of their masses is
$1:2$
$1:1$
$4:1$
$1:4$
Two particles of the same mass are moving in circular orbits because of force, given by $F(r) = \frac{{ - 16}}{r}\, - \,{r^3}$ The first particle is at a distance $r = 1,$ and the second, at $r = 4.$ The best estimate for the ratio of kinetic energies of the first and the second particle is closest to
If the momentum of a body is increased $n$ times, its kinetic energy increases
A particle of mass $ M$ is moving in a horizontal circle of radius $R$ with uniform speed $V$. When it moves from one point to a diametrically opposite point, its
A lift of mass $M =500\,kg$ is descending with speed of $2\,ms ^{-1}$. Its supporting cable begins to slip thus allowing it to fall with a constant acceleration of $2\,ms ^{-2}$. The kinetic energy of the lift at the end of fall through to a distance of $6 m$ will be $...........kJ.$
For the pulley system the kinetic energy of the $6\,kg$ block after $5\,s$ is ............ $\mathrm{J}$