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14.Probability
medium
Two cards are drawn without replacement from a well-shuffled pack. Find the probability that one of them is an ace of heart
A
$\frac{1}{{25}}$
B
$\frac{1}{{26}}$
C
$\frac{1}{{52}}$
D
None of these
Solution
(b) There are two conditions.
$(i)$ When first is an ace of heart and second one is non-ace of heart
$ = \frac{1}{{52}} \times \frac{{51}}{{52}}\, \Rightarrow \frac{1}{{52}}$
$(ii)$ When first is non-ace of heart and second one is an ace of heart
$ = \frac{{51}}{{52}} \times \frac{1}{{51}} = \frac{1}{{52}}$
$\therefore$ Required probability $ = \frac{1}{{52}} + \frac{1}{{52}} = \frac{1}{{26}}.$
Standard 11
Mathematics
