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1. Electric Charges and Fields
easy
Two charges ${q_1}$ and ${q_2}$ are placed in vacuum at a distance $d$ and the force acting between them is $F$. If a medium of dielectric constant $4$ is introduced around them, the force now will be
A
$4F$
B
$2F$
C
$\frac{F}{2}$
D
$\frac{F}{4}$
Solution
(d) In the presence of medium force becomes $\frac{1}{K}times$.
Standard 12
Physics
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