Gujarati
1. Electric Charges and Fields
easy

Two charges ${q_1}$ and ${q_2}$ are placed in vacuum at a distance $d$ and the force acting between them is $F$. If a medium of dielectric constant $4$ is introduced around them, the force now will be

A

$4F$

B

$2F$

C

$\frac{F}{2}$

D

$\frac{F}{4}$

Solution

(d) In the presence of medium force becomes $\frac{1}{K}times$.

Standard 12
Physics

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