- Home
- Standard 12
- Physics
1. Electric Charges and Fields
hard
Two charges of $5 Q$ and $-2 Q$ are situated at the points $(3 a, 0)$ and $(-5 a, 0)$ respectively. The electric flux through a sphere of radius $4a$ having center at origin is
A
$\frac{2 Q}{\varepsilon_0}$
B
$\frac{5 \mathrm{Q}}{\varepsilon_0}$
C
$\frac{7 Q}{\varepsilon_0}$
D
$\frac{3 Q}{\varepsilon_0}$
(JEE MAIN-2024)
Solution
$5 \mathrm{Q}$ charge is inside the spherical region flux through sphere $=\frac{5 \mathrm{Q}}{\varepsilon_0}$
Standard 12
Physics
