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1. Electric Charges and Fields
easy
Two charges of equal magnitudes and at a distance $r$ exert a force $F$ on each other. If the charges are halved and distance between them is doubled, then the new force acting on each charge is
A
$F / 8$
B
$F / 4$
C
$4 F$
D
$F / 16$
Solution
(d) $F = k.\frac{{{Q^2}}}{{{r^2}}}$. If $Q$ is halved, $r$ is doubled then $F \to \frac{1}{{16}}{\rm{times}}$
Standard 12
Physics