2. Electric Potential and Capacitance
easy

Two conducting shells of radius $a$ and $b$ are connected by conducting wire as shown in figure. The capacity of system is :

A

$4 \pi \varepsilon_0 \frac{a b}{b-a}$

B

$4 \pi \varepsilon_0(a+b)$

C

$zero$

D

infinite

Solution

(d)

$V=0$, and so $C=\frac{q}{V} \rightarrow \infty$

Standard 12
Physics

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