Two dielectric slabs of constant {K₁} and {K₂} have been filled in between plates of a capacitor

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2. Electric Potential and Capacitance

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Two dielectric slabs of constant ${K_1}$ and ${K_2}$ have been filled in between the plates of a capacitor as shown below. What will be the capacitance of the capacitor

A

$\frac{{2{\varepsilon _0}A}}{2}({K_1} + {K_2})$

B

$\frac{{2{\varepsilon _0}A}}{2}\left( {\frac{{{K_1} + {K_2}}}{{{K_1} \times {K_2}}}} \right)$

C

$\frac{{2{\varepsilon _0}A}}{2}\left( {\frac{{{K_1} \times {K_2}}}{{{K_1} + {K_2}}}} \right)$

D

$\frac{{2{\varepsilon _0}A}}{d}\left( {\frac{{{K_1} \times {K_2}}}{{{K_1} + {K_2}}}} \right)$

Solution

(d) The two capacitors formed by the slabs may assumed to be in series combination.

Standard 12

Physics

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