Two dielectric slabs of constant ${K_1}$ and ${K_2}$ have been filled in between the plates of a capacitor as shown below. What will be the capacitance of the capacitor
$\frac{{2{\varepsilon _0}A}}{2}({K_1} + {K_2})$
$\frac{{2{\varepsilon _0}A}}{2}\left( {\frac{{{K_1} + {K_2}}}{{{K_1} \times {K_2}}}} \right)$
$\frac{{2{\varepsilon _0}A}}{2}\left( {\frac{{{K_1} \times {K_2}}}{{{K_1} + {K_2}}}} \right)$
$\frac{{2{\varepsilon _0}A}}{d}\left( {\frac{{{K_1} \times {K_2}}}{{{K_1} + {K_2}}}} \right)$
If the distance between the plates of parallel plate capacitor is halved and the dielectric constant of dielectric is doubled, then its capacity will
A sheet of aluminium foil of negligible thickness is introduced between the plates of a capacitor. The capacitance of the capacitor
A combination of parallel plate capacitors is maintained at a certain potential difference When a $3\, mm$ thick slab is introduced between all the plates, in order to maintain the same potential difference, the distance between the plates is increased by $2.4\, mm$. Find the dielectric constant of the slab.
A parallel plate capacitor has two layers of dielectrics as shown in fig. This capacitor is connected across a battery, then the ratio of potential difference across the dielectric layers is
A medium having dielectric constant $K>1$ fills the space between the plates of a parallel plate capacitor. The plates have large area, and the distance between them is $d$. The capacitor is connected to a battery of voltage $V$. as shown in Figure ($a$). Now, both the plates are moved by a distance of $\frac{d}{2}$ from their original positions, as shown in Figure ($b$).
In the process of going from the configuration depicted in Figure ($a$) to that in Figure ($b$), which of the following statement($s$) is(are) correct?