14.Probability
normal

Two digits are selected randomly from the set $\{1, 2,3, 4, 5, 6, 7, 8\}$ without replacement one by one. The probability that minimum of the two digits is less than $5$ is

A

$\frac {3}{14}$

B

$\frac {11}{14}$

C

$\frac {5}{14}$

D

$\frac {9}{14}$

Solution

Required probability
$= 1 -$ (probability that both the digit are greater than $5$)

$ = 1 – \frac{{{}^4{C_2}}}{{{}^8{C_2}}} = \frac{{11}}{{14}}$

Standard 11
Mathematics

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