Two identical satellites A and B are circulating round earth at height of R and 2R respectively, (wh

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7.Gravitation

medium

Two identical satellites $A$ and $B$ are circulating round the earth at the height of $R$ and $2R$ respectively, (where $R$ is radius of the earth). The ratio of kinetic energy of $A$ to that of $B$ is

$\frac{1}{2}$

$\frac{2}{3}$

$2$

$\frac{3}{2}$

Solution

(d) $\frac{{{K_A}}}{{{K_B}}} = \frac{{{r_B}}}{{{r_A}}} = \left( {\frac{{R + {h_B}}}{{R + {h_A}}}} \right) = \left( {\frac{{R + 2R}}{{R + R}}} \right) = \frac{3}{2}$

Standard 11

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medium

Two identical satellites $A$ and $B$ are circulating round the earth at the height of $R$ and $2R$ respectively, (where $R$ is radius of the earth). The ratio of kinetic energy of $A$ to that of $B$ is

Solution

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