Two masses A and B of 10,kg and 5,kg respectively are connected with a string passing over a fricion

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4-1.Newton's Laws of Motion

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Two masses $A$ and $B$ of $10\,kg$ and $5\,kg$ respectively are connected with a string passing over a fricionless pulley fixed at the corner of a table as show $n$ in figure. The coefficient of friction of $A$ with the table is $0.2$ . The minimum mass of $C$ that may be placed on $A$ to prevent if from moving is equal to $...........\,kg$

A

$5$

B

$10$

C

$15$

D

$0$

Solution

System is at rest contract

So,

At rest

$t=T=\mu N$

$N=50 / 0.2=250 \text { newton }$

$\text { so } m_c=15\,kg$

Standard 11

Physics

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