A capacitor is charged by using a battery which is then disconnected. A dielectric slab is introduced between the plates which results in

  • [AIIMS 2010]
  • A

    increase in the potential difference across the plates and reduction in stored energy but no change in the charge on the plates

  • B

    decrease in the potential difference across the plates and reduction in the stored energy but no change in the charge on the plates

  • C

    reduction of charge on the plates and increase of potential difference across the plates

  • D

    increase in stored energy but no change in potential difference across the plates

Similar Questions

A parallel-plate capacitor of area $A,$ plate separation $d$ and capacitance $C$ is filled with four dielectric materials having dielectric constants $K_1,K_2,K_3$ and $K_4$ as shown in the figure. If a single dielectric material is to be used to have the same capacitance $C$ in this capacitor, then its dielectric constant $K$ is given by 

  • [NEET 2016]

A parallel plate capacitor of plate area $A$ and plate separation $d$ is charged to potential $V$ and then the battery is disconnected. A slab of dielectric constant $k$ is then inserted between the plates of the capacitors so as to fill the space between the plates. If $Q,\;E$ and $W$ denote respectively, the magnitude of charge on each plate, the electric field between the plates (after the slab is inserted) and work done on the system in question in the process of inserting the slab, then state incorrect relation from the following

  • [IIT 1991]

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