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2. Electric Potential and Capacitance
easy
Two points $P$ and $Q$ are maintained at the potentials of $10\, V$ and $-4\,V$, respectively. The work done in moving $100$ electrons from $P$ and $Q$ is
A
$-9.60\times10^{-17}\, J$
B
$9.60\times10^{-17}\, J$
C
$-2.24\times10^{-16}\, J$
D
$2.24\times10^{-16}\, J$
Solution
$ \mathrm{W} =100 \mathrm{e}(-4-10)=-1400 \mathrm{\,eV} $
$=-1400\left(-1.6 \times 10^{-19}\right) \mathrm{\,J}=2.24 \times 10^{-16} \mathrm{\,J} $
Standard 12
Physics
