Two simple pendulums of lengths 1.44 ,m and 1, m start swinging together. After how many vibrations

English

Gujarati

Hindi

13.Oscillations

medium

Two simple pendulums of lengths $1.44 \,m$ and $1\, m$ start swinging together. After how many vibrations will they again start swinging together

A

$5$ oscillations of smaller pendulum

B

$6$ oscillations of smaller pendulum

C

$4$ oscillations of bigger pendulum

D

$6$ oscillations of bigger pendulum

Solution

(b) $n \propto \frac{1}{{\sqrt l }}$==> $\frac{{{n_2}}}{{{n_1}}}$$ = \sqrt {\frac{{1.44}}{1}} = \frac{{1.2}}{1}$==> ${n_2} = 1.2\,{n_1}$

For $n2$ be integer minimum value of $n1$ should be $5$ and then $n2 = 6$ i.e., after $6 $ oscillations of smaller pendulum both will be in phase.

Standard 11

Physics

Share

Similar Questions

A girl is swinging a swing in the sitting position. What will be the effect on the time period of the swing if she stand up ?

easy

A hollow sphere is filled with water through a small hole in it. It is then hung by a long thread and made to oscillate. As the water slowly flows out of the hole at the bottom, the period of oscillation will

medium

(KVPY-2010)

The periodic time of a simple pendulum of length $1\, m $ and amplitude $2 \,cm $ is $5\, seconds$. If the amplitude is made $4\, cm$, its periodic time in seconds will be

easy

A simple pendulum is suspended from the roof of a trolley which moves in a horizontal direction with an acceleration $a$, then the time period is given by $T = 2\pi \sqrt {\frac{l}{{g'}}} $, where $g'$ is equal to

medium

(AIPMT-1991)

There is a simple pendulum hanging from the ceiling of a lift. When the lift is stand still, the time period of the pendulum is $T$. If the resultant acceleration becomes $g/4,$ then the new time period of the pendulum is

easy