Two small spheres each having the charge $ + Q$ are suspended by insulating threads of length $L$ from a hook. This arrangement is taken in space where there is no gravitational effect, then the angle between the two suspensions and the tension in each will be
${180^o},\,\frac{1}{{4\pi {\varepsilon _0}}}\frac{{{Q^2}}}{{{{(2L)}^2}}}$
${90^o},\,\frac{1}{{4\pi {\varepsilon _0}}}\frac{{{Q^2}}}{{{L^2}}}$
${180^o},\,\frac{1}{{4\pi {\varepsilon _0}}}\frac{{{Q^2}}}{{2{L^2}}}$
${180^o},\,\frac{1}{{4\pi {\varepsilon _0}}}\frac{{{Q^2}}}{{{L^2}}}$
When the distance between the charged particles is halved, the force between them becomes
The ratio of gravitational force and electrostatic repulsive force between two electrons is approximately (gravitational constant $=6.7 \times 10^{-11} \,Nm ^2 / kg ^2$, mass of an electron $=9.1 \times 10^{-31} \,kg$, charge on an electron $=1.6 \times 10^{-19} C$ )
Four charges equal to $-Q$ are placed at the four corners of a square and a charge $q$ is at its centre. If the system is in equilibrium the value of $q$ is
The electrostatic force on a small sphere of charge $0.4 \;\mu\, C$ due to another small sphere of charge $-0.8 \;\mu \,C$ in air is $0.2\; N .$
$(a)$ What is the distance between the two spheres?
$(b)$ What is the force on the second sphere due to the first?
$A$ and $B$ are two identical blocks made of a conducting material. These are placed on a horizontal frictionless table and connected by a light conducting spring of force constant $‘K’$. Unstretched length of the spring is $L_0$. Charge $Q/2$ is given to each block. Consequently, the spring stretches to an equilibrium length $L$. Value of $Q$ is