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1. Electric Charges and Fields
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A point charge of $40$ stat coulomb is placed $2$ $cm$ in front of an earthed metallic plane plate of large size. Then the force of attraction on the point charge is.....$dynes$
A
$100$
B
$160$
C
$1600$
D
$400$
Solution
(a) By the concept of electrical image, it is considered that an equal but opposite charge present on the other side of the plate at equal distance. Hence force
$F = \frac{{40 \times 40}}{{{4^2}}} = 100\,dynes$
Standard 12
Physics
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