Gujarati
1. Electric Charges and Fields
medium

A point charge of $40$ stat coulomb is placed $2$ $cm$ in front of an earthed metallic plane plate of large size. Then the force of attraction on the point charge is.....$dynes$

A

$100$

B

$160$

C

$1600$

D

$400$

Solution

(a) By the concept of electrical image, it is considered that an equal but opposite charge present on the other side of the plate at equal distance. Hence force
$F = \frac{{40 \times 40}}{{{4^2}}} = 100\,dynes$

Standard 12
Physics

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