Three point charges q,-2 q and 2 q are placed on x -axis at a distance x=0, x=frac{3}{4} R and x=R r

English

Gujarati

Hindi

1. Electric Charges and Fields

medium

Three point charges $q,-2 q$ and $2 q$ are placed on $x$-axis at a distance $x=0, x=\frac{3}{4} R$ and $x=R$ respectively from origin as shown. If $q =2 \times 10^{-6}\,C$ and $R =2\,cm$, the magnitude of net force experienced by the charge $-2 q$ is .......... $N$

A

$5442$

B

$5440$

C

$5448$

D

$5475$

(JEE MAIN-2023)

Solution

$F _{ BA }=\frac{ Kq (2 q )}{\left(\frac{3}{4} R \right)^2}=\frac{32 Kq ^2}{9 R ^2}$

$F _{ BC }=\frac{ K (2 q )(2 q )}{\left(\frac{ R }{4}\right)^2}=\frac{64 Kq ^2}{ R ^2}$

$F _{ B }= F _{ BC }- F _{ BA }=\frac{544 Kq ^2}{9 R ^2}$

$=\frac{544 \times 9 \times 10^9 \times\left(2 \times 10^{-6}\right)^2}{9 \times\left(2 \times 10^{-2}\right)^2}=5440\,N$

Standard 12

Physics

Share

Similar Questions

A given charge is situated at a certain distance from an electric dipole in the end-on position experiences a force $F$. If the distance of the charge is doubled, the force acting on the charge will be

easy

$ + 2\,C$ and $ + 6\,C$ two charges are repelling each other with a force of $12\,N$. If each charge is given $ – 2\,C$ of charge, then the value of the force will be

easy

Two particles $X $ and $Y$, of equal mass and with unequal positive charges, are free to move and are initially far away from each other. With $Y$ at rest, $X$ begins to move towards it with initial velocity $u$. After a long time, finally

hard

$A$ and $B$ are two identical blocks made of a conducting material. These are placed on a horizontal frictionless table and connected by a light conducting spring of force constant $‘K’$. Unstretched length of the spring is $L_0$. Charge $Q/2$ is given to each block. Consequently, the spring stretches to an equilibrium length $L$. Value of $Q$ is

medium

Two charges of equal magnitudes and at a distance $r$ exert a force $F$ on each other. If the charges are halved and distance between them is doubled, then the new force acting on each charge is

easy