Two sources of light emit with a power of 200 mathrm{~W} . ratio of number of photons of visible lig

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11.Dual Nature of Radiation and matter

hard

Two sources of light emit with a power of $200 \mathrm{~W}$. The ratio of number of photons of visible light emitted by each source having wavelengths $300\ \mathrm{nm}$ and $500 \mathrm{~nm}$ respectively, will be :

A

$1: 5$

B

$1: 3$

C

$5: 3$

D

$3: 5$

(JEE MAIN-2024)

Solution

$ \mathrm{n}_1 \times \frac{\mathrm{hc}}{\lambda_1}=200 $

$ \mathrm{n}_2 \times \frac{\mathrm{hc}}{\lambda_2}=200 $

$ \frac{\mathrm{n}_{\mathrm{l}}}{\mathrm{n}_2}=\frac{\lambda_1}{\lambda_2}=\frac{300}{500} $

$ \frac{\mathrm{n}_1}{\mathrm{n}_2}=\frac{3}{5}$

Standard 12

Physics

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