Two stones having different masses m₁ and m₂ are projected at an angle α and left(90^{circ}-αr

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3-2.Motion in Plane

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Two stones having different masses $m_1$ and $m_2$ are projected at an angle $\alpha$ and $\left(90^{\circ}-\alpha\right)$ with same speed from same point. The ratio of their maximum heights is

A

$1: 1$

B

$1: \tan \alpha$

C

$\tan \alpha: 1$

D

$\tan ^2 \alpha: 1$

Solution

(d)

$H \propto \sin \alpha$

$\therefore \quad \frac{H_1}{H_2}=\frac{\sin ^2 \alpha}{\sin ^2\left(90^{\circ}-\alpha\right)}=\tan ^2 \alpha$

Standard 11

Physics

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