- Home
- Standard 12
- Physics
11.Dual Nature of Radiation and matter
easy
$1\; keV$ ऊर्जा वाले फोटॉन की तरंगदैध्र्य $1.24 \times {10^{ - 9}}\;m$ है तो $1\;MeV$ वाले फोटॉन की आवृत्ति होगी
A
$1.24 \times {10^{15}}\;Hz$
B
$2.4 \times {10^{20}}\;Hz$
C
$1.24 \times {10^{18}}\;Hz$
D
$2.4 \times {10^{23}}\;Hz$
(AIPMT-1991)
Solution
$E = h\nu \, $
$\Rightarrow \,\nu = \frac{E}{h} = \frac{{1 \times {{10}^6} \times 1.6 \times {{10}^{ – 19}}}}{{6.6 \times {{10}^{ – 34}}}}$$ = 2.4 \times {10^{20}}\,Hz$
Standard 12
Physics
