What is the magnitude of the equatorial and axial fields due to a bar magnet of length $5.0 \;cm$ at a distance of $50\; cm$ from its mid-point? The magnetic moment of the bar magnet is $0.40\; A m ^{2}$.

Vedclass pdf generator app on play store
Vedclass iOS app on app store

$B_{E}=\frac{\mu_{0} m}{4 \pi r^{3}}=\frac{10^{-7} \times 0.4}{(0.5)^{3}}=\frac{10^{-7} \times 0.4}{0.125}$$=3.2 \times 10^{-7} T$

$B_{A}=\frac{\mu_{0} 2 \,m}{4 \pi r^{3}}=6.4 \times 10^{-7} T$

Similar Questions

Two bar magnets with magnetic moments $ 2 M $ and $M$ are fastened together at right angles to each other at their centres to form a crossed system, which can rotate freely about a vertical axis through the centre. The crossed system sets in earth’s magnetic field with magnet having magnetic moment $2M $ making and angle  $ \theta $ with the magnetic meridian such that

What is the difference between Gauss’s law in electrostatics and Gauss’s law in magnetism ?

A magnetic needle is kept in a non-uniform magnetic field. It experiences

  • [AIEEE 2005]

The distance of two points on the axis of a magnet from its centre is $10 \,cm$  and $20 \,cm$  respectively. The ratio of magnetic intensity at these points is $12.5 : 1. $ The length of the magnet will be......$cm$

A straight magnetic strip has a magnetic moment of $44 \mathrm{Am}^2$. If the strip is bent in a semicircular shape, its magnetic moment will be .. . . . . . .$\mathrm{Am}^2$ $\left(\right.$ Given $\left.\pi=\frac{22}{7}\right)$

  • [JEE MAIN 2024]