Magnitude of equatorial and axial fields due to a bar magnet of length 5.0 cm at a distance of 50 cm

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5.Magnetism and Matter

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What is the magnitude of the equatorial and axial fields due to a bar magnet of length $5.0 \;cm$ at a distance of $50\; cm$ from its mid-point? The magnetic moment of the bar magnet is $0.40\; A m ^{2}$.

Option A

Option B

Option C

Option D

Solution

$B_{E}=\frac{\mu_{0} m}{4 \pi r^{3}}=\frac{10^{-7} \times 0.4}{(0.5)^{3}}=\frac{10^{-7} \times 0.4}{0.125}$$=3.2 \times 10^{-7} T$

$B_{A}=\frac{\mu_{0} 2 \,m}{4 \pi r^{3}}=6.4 \times 10^{-7} T$

Standard 12

Physics

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