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4-2.Friction
hard
મહત્તમ બળ $F$ ........ $N$ રાખવાથી બ્લોક ખસે નહિ.
A
$20$
B
$10$
C
$12$
D
$15$
(IIT-2003)
Solution
(a) $f = \mu R$
$F\cos 60^\circ = \mu (W + F\sin 60^\circ )$
Substituting $\mu = \frac{1}{{2\sqrt 3 }}$ & $W = 10\sqrt 3 $
we get $F = 20\,N$
Standard 11
Physics
