Velocity of bob of a simple pendulum at its mean position, if it is able to rise to vertical height

English

Gujarati

Hindi

13.Oscillations

easy

What is the velocity of the bob of a simple pendulum at its mean position, if it is able to rise to vertical height of $10\,cm$ ($g = 9.8\, m/s^2$) ..... $m/s$

$2.2$

$1.8$

$1.4$

$0.6$

Solution

(c) According to the principle of conservation of energy, $\frac{1}{2}m{v^2} = mgh$ or $v = \sqrt {2gh} = \sqrt {2 \times 9.8 \times 0.1} $ $ = 1.4\,m/s.$

Standard 11

Physics

What is linear harmonic oscillator ? And what is non-linear oscillator ?

medium

If the length of a clock pendulum increases by $0.2 \%$ due to atmospheric temperature rise, then the loss in time of clock per day is ……….. $s$

medium

A simple pendulum has time period 't'. Its time period in a lift which is moving upwards with acceleration $3 ms ^{-2}$ is

easy

In a seconds pendulum, mass of bob is $30\, g$. If it is replaced by $90\, g$ mass. Then its time period will be … $\sec$

easy

The bob of a pendulum was released from a horizontal position. The length of the pendulum is $10 \mathrm{~m}$. If it dissipates $10 \%$ of its initial energy against air resistance, the speed with which the bob arrives at the lowest point is : [Use, $\mathrm{g}: 10 \mathrm{~ms}^{-2}$ ]

hard

(JEE MAIN-2024)

What is the velocity of the bob of a simple pendulum at its mean position, if it is able to rise to vertical height of $10\,cm$ ($g = 9.8\, m/s^2$) ..... $m/s$

Solution

Similar Questions

What is linear harmonic oscillator ? And what is non-linear oscillator ?

If the length of a clock pendulum increases by $0.2 \%$ due to atmospheric temperature rise, then the loss in time of clock per day is ……….. $s$

A simple pendulum has time period 't'. Its time period in a lift which is moving upwards with acceleration $3 ms ^{-2}$ is

In a seconds pendulum, mass of bob is $30\, g$. If it is replaced by $90\, g$ mass. Then its time period will be … $\sec$

The bob of a pendulum was released from a horizontal position. The length of the pendulum is $10 \mathrm{~m}$. If it dissipates $10 \%$ of its initial energy against air resistance, the speed with which the bob arrives at the lowest point is : [Use, $\mathrm{g}: 10 \mathrm{~ms}^{-2}$ ]

Start a Free Trial Now