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8.Mechanical Properties of Solids
easy
When a block of mass $M$ is suspended by a long wire of length $L$, the length of the wire become $(L+l) .$ The elastic potential energy stoped in the extended wire is :
A
$Mgl$
B
$MgL$
C
$\frac{1}{2} Mgl$
D
$\frac{1}{2} \mathrm{MgL}$
(NEET-2019)
Solution
$\mathrm{U}=\frac{1}{2}$ (force) (elongation)
$=\frac{1}{2}(M g) \ell=\frac{1}{2} M g \ell$
Standard 11
Physics