8.Mechanical Properties of Solids
easy

When a block of mass $M$ is suspended by a long wire of length $L$, the length of the wire become $(L+l) .$ The elastic potential energy stoped in the extended wire is :

A

$Mgl$

B

$MgL$

C

$\frac{1}{2} Mgl$

D

$\frac{1}{2} \mathrm{MgL}$

(NEET-2019)

Solution

$\mathrm{U}=\frac{1}{2}$ (force) (elongation)

$=\frac{1}{2}(M g) \ell=\frac{1}{2} M g \ell$

Standard 11
Physics

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