When a gas expands adiabatically
No energy is required for expansion
Energy is required and it comes from the wall of the container of the gas
Internal energy of the gas is used in doing work
Law of conservation of energy does not hold
The work done in an adiabatic change in a gas depends only on
An ideal gas at pressure $P$ and volume $V$ is expanded to volume$ 2V.$ Column $I$ represents the thermodynamic processes used during expansion. Column $II$ represents the work during these processes in the random order.:
Column $I$ | Column $II$ |
$(p)$ isobaric | $(x)$ $\frac{{PV(1 - {2^{1 - \gamma }})}}{{\gamma - 1}}$ |
$(q)$ isothermal | $(y)$ $PV$ |
$(r)$ adiabatic | (z) $PV\,\iota n\,2$ |
The correct matching of column $I$ and column $II$ is given by
$Assertion :$ Adiabatic expansion is always accompanied by fall in temperature.
$Reason :$ In adiabatic process, volume is inversely proportional to temperature.
Consider a cycle tyre being filled with air by a pump. Let $V$ be the volume of the tyre (fixed) and at each stroke of the pump $\Delta V$ $(< < V)$ of air is transferred to the tube adiabatically. What is the work done when the pressure in the tube is increased from $P_1$ to $P_2$ ?
Which is the correct statement