When a mass m is attached to a spring, it normally extends by 0.2, m . mass m is given a slight addi

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13.Oscillations

easy

When a mass $m$ is attached to a spring, it normally extends by $0.2\, m$. The mass $m$ is given a slight addition extension and released, then its time period will be

A

$\frac{1}{7}\, sec$

B

$1\, sec$

C

$\frac{{2\pi }}{7}\,sec$

D

$\frac{2}{{3\pi }}\,sec$

Solution

(c) $Kx = mg$

$\Rightarrow \frac{m}{K} = \frac{x}{g}$

So $T = 2\pi \sqrt {\frac{m}{K}} = 2\pi \sqrt {\frac{x}{g}} = 2\pi \sqrt {\frac{{0.2}}{{9.8}}} = \frac{{2\pi }}{7}\sec $

Standard 11

Physics

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