Gujarati
Hindi
1. Electric Charges and Fields
normal

When a proton is accelerated through $1\,V,$ then its kinetic energy will be........$eV$

A

$1840$

B

$13.6$

C

$1$

D

$0.54$

Solution

$\Delta KE = qV = eV = e \times 1\,V = 1\,eV$

Standard 12
Physics

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