- Home
- Standard 11
- Physics
5.Work, Energy, Power and Collision
medium
When a spring is stretched by $2\, cm$, it stores $100 \,J$ of energy. If it is stretched further by $2 \,cm$, the stored energy will be increased by ............. $\mathrm{J}$
A
$100$
B
$200$
C
$300$
D
$400$
Solution
(c)$100 = \frac{1}{2}k{x^2}$ (given)
$W = \frac{1}{2}k(x_2^2 – x_1^2) = \frac{1}{2}k[{(2x)^2} – {x^2}]$
$ = 3 \times \left( {\frac{1}{2}k{x^2}} \right) = 3 \times 100 = 300\,J$
Standard 11
Physics
Similar Questions
hard
