When a system is taken from thermodynamic state i to f along path iaf (see figure), it is found that

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11.Thermodynamics

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When a system is taken from thermodynamic state $i$ to $f$ along the path $iaf$ (see figure), it is found that the heat $Q$ absorbed by the system is $50\ cal$ and work $W$ done by the system is equal to $20\ cal$ . Along the path ibf $Q = 36\ cal$ . What is $W$ along the path ibf? ........... $\mathrm{cal}$

A

$6$

B

$18$

C

$40$

D

$-43$

Solution

Along path iaf,

$\mathrm{dQ}=\mathrm{dU}+\mathrm{dW}$

$50=d U+20$

$\mathrm{d} \mathrm{U}=30 \mathrm{\,cal}$

Along path ibf,

$\mathrm{dQ}=\mathrm{dU}+\mathrm{dW}$

$36=30+d W $

$d W=6 \text { cal }$

Standard 11

Physics

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