When one electron is taken towards other electron, then electric potential energy of system

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2. Electric Potential and Capacitance

easy

When one electron is taken towards the other electron, then the electric potential energy of the system

Decreases

Increases

Remains unchanged

Becomes zero

(AIPMT-1993) (AIPMT-1999)

Solution

(b) Potential energy of the system will be given by $ = \frac{{( – e)\,( – e)}}{{4\pi {\varepsilon _0}r}} = \frac{{{e^2}}}{{4\pi {\varepsilon _0}r}}$
As $r$ decreases, potential energy increases.

Standard 12

Physics

A circle of radius $R$ is drawn with charge $+ q$ at the centre. A charge $q_0$ is brought from point $B$ to $C$, then work done is

easy

(AIIMS-2009)

If $OP = 1\,\,cm$ and $OS = 2\,\, cm$, work done by electric field in shifting a point charge $\frac {4\sqrt 2}{27}\,\, μC$ from point $P$ to $S$ in given figure is

medium

A particle of mass $m$ having negative charge $q$ move along an ellipse around a fixed positive charge $Q$ so that its maximum and minimum distances from fixed charge are equal to $r_1$ and $r_2$ respectively. The angular momentum $L$ of this particle is

hard

A negatively charged plate has charge density of $2 \times {10^{ – 6}}\,C/{m^2}$. The initial distance of an electron which is moving toward plate, cannot strike the plate, if it is having energy of $200\,eV$