Which of the following statement is not correct about diborane?
Which of the following statement is not correct about diborane?
- [NEET 2022]
- A
The four terminal $B-H$ bonds are two centre two electron bonds.
- B
The four terminal Hydrogen atoms and the two Boron atoms lie in one plane.
- C
Both the Boron atoms are $s p^{2}$ hybridised.
- D
There are two $3-$centre$-2-$electron bonds.
Similar Questions
Suggest reasons why the $B-F$ bond lengths in $BF $$_{3}(130 \,pm )$ and $B F_{4}^{-}(143\, pm )$ differ.
Suggest reasons why the $B-F$ bond lengths in $BF $$_{3}(130 \,pm )$ and $B F_{4}^{-}(143\, pm )$ differ.
The electrochemical extraction of aluminum from bauxite ore involves.
$(A)$ the reaction of $Al _2 O _3$ with coke ($C$) at a temperature $>2500^{\circ} C$.
$(B)$ the neutralization of aluminate solution by passing $CO _2$ gas to precipitate hydrated alumina $\left( Al _2 O _3 .3 H _2 O \right)$
$(C)$ the dissolution of $Al _2 O _3$ in hot aqueous $NaOH$.
$(D)$ the electrolysis of $Al _2 O _3$ mixed with $Na _3 AlF _6$ to give $Al$ and $CO _2$.
The electrochemical extraction of aluminum from bauxite ore involves.
$(A)$ the reaction of $Al _2 O _3$ with coke ($C$) at a temperature $>2500^{\circ} C$.
$(B)$ the neutralization of aluminate solution by passing $CO _2$ gas to precipitate hydrated alumina $\left( Al _2 O _3 .3 H _2 O \right)$
$(C)$ the dissolution of $Al _2 O _3$ in hot aqueous $NaOH$.
$(D)$ the electrolysis of $Al _2 O _3$ mixed with $Na _3 AlF _6$ to give $Al$ and $CO _2$.
- [IIT 2022]
Colour of the bead in borax bead test is mainly due to the formation of
Colour of the bead in borax bead test is mainly due to the formation of
Write balanced equations for:
$(i)$ $BF _{3}+ LiH \rightarrow$
$(ii)$ $B _{2} H _{6}+ H _{2} O \rightarrow$
$(\text { iii }) NaH + B _{2} H _{6} \rightarrow$
$(i v) H_{3} B O_{3} \stackrel{\Delta}{\longrightarrow}$
$( v ) Al + NaOH \rightarrow$
$( v i ) B _{2} H _{6}+ NH _{3} \rightarrow$
Write balanced equations for:
$(i)$ $BF _{3}+ LiH \rightarrow$
$(ii)$ $B _{2} H _{6}+ H _{2} O \rightarrow$
$(\text { iii }) NaH + B _{2} H _{6} \rightarrow$
$(i v) H_{3} B O_{3} \stackrel{\Delta}{\longrightarrow}$
$( v ) Al + NaOH \rightarrow$
$( v i ) B _{2} H _{6}+ NH _{3} \rightarrow$
The incorrect statement regarding above reactions is
$\mathop {Al}\limits_{metal} \xrightarrow[{(aq.)}]{{HCl}}'X' + Gas\,'P'$
$\mathop {Al}\limits_{metal} \xrightarrow[{ + {H_2}O}]{{NaOH\,(aq.)}}'Y' + Gas\,'Q'$
The incorrect statement regarding above reactions is
$\mathop {Al}\limits_{metal} \xrightarrow[{(aq.)}]{{HCl}}'X' + Gas\,'P'$
$\mathop {Al}\limits_{metal} \xrightarrow[{ + {H_2}O}]{{NaOH\,(aq.)}}'Y' + Gas\,'Q'$