Write analogy between electrostatic and magnetism.
Physical quantity | Electrostatic | Magnetism |
$(1)$ Field | Electric field $\overrightarrow{\mathrm{E}}$ | Magnetic field $B$ |
$(2)$ Pole strength | Charge $(q)$ | Pole $\left(q_{\mathrm{m}}\right)$ |
$(3)$ Dipole moment | $p=q(2 a)$ | $m=q_{\mathrm{m}}(2 l)$ |
$(4)$ Constant | $\frac{1}{4 \pi \in_{0}}$ | $\frac{\mu_{0}}{4 \pi}$ |
$(5)$ Length of dipole | $2 a$ | $2 l$ |
$(6)$ Direction of dipole moment |
From negative charge to positive charge |
From south pole to north pole |
A magnet of magnetic moment $M$ and pole strength $m$ is divided in two equal parts, then magnetic moment of each part will be
The dipole moment of a short bar magnet is $1.25\, A-m^2$. The magnetic field on its axis at a distance of $0.5$ metre from the centre of the magnet is
The magnetic potential at a point on the axial line of a bar magnet of dipole moment $M$ is $V$. What is the magnetic potential due to a bar magnet of dipole moment $\frac{M}{4}$ at the same point
A small magnetised needle $P$ placed at point $O$ and the arrow shows the direction of its magnetic moment. The other arrow show different position (and orientation) of another identical magnets $(Q)$. In which configuration system is not in equilibrium
The field due to a magnet at a distance $ R$ from the centre of the magnet is proportional to