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1.Set Theory
easy
સમીકરણ ${x^2} + x - 2 = 0$ ના ઉકેલગણને યાદીની રીતે લખો.
A
$(1,-2)$
B
$(1,-2)$
C
$(1,-2)$
D
$(1,-2)$
Solution
The given equation can be written as
$\left( {x – 1} \right)\left( {x – 2} \right) = 0,$ i.e., $x=1,-2 $
Therefore, the solution set of the given equation can be written in roster form as $\{ 1, – 2\} $
Standard 11
Mathematics
