sumlimits_{r = 1}^{100} {frac{{tan ,{2^{r - 1 | vedclass

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Question

$\mathrm{T}_{\mathrm{x}}=\frac{	an 2^{\mathrm{r}-1}}{\cos 2^{\mathrm{r}}}=	an 2^{\mathrm{r}}-	an 2^{\mathrm{r}-1}$

$ \Rightarrow \sum\limits_{r

Vedclass · Accepted Answer

$tan\,2^{100} -tan\,1$

Vedclass · Answer

$\mathrm{T}_{\mathrm{x}}=\frac{	an 2^{\mathrm{r}-1}}{\cos 2^{\mathrm{r}}}=	an 2^{\mathrm{r}}-	an 2^{\mathrm{r}-1}$

$ \Rightarrow \sum\limits_{r = 1}^{100} {{T_r} = 	an {2^{100}} - 	an 1} $

$\sum\limits_{r = 1}^{100} {\frac{{\tan \,{2^{r - 1}}}}{{\cos \,{2^r}}}} $ is equal to

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