0.2 molar solution of formic acid is ionized 3.2% . Its ionization constant is

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6-2.Equilibrium-II (Ionic Equilibrium)

easy

$0.2$ molar solution of formic acid is ionized $3.2\%$. Its ionization constant is

A

$1 \times {10^{ - 12}}$

B

$2.1 \times {10^{ - 4}}$

C

$1.25 \times {10^{ - 6}}$

D

$1 \times {10^{ - 14}}$

Solution

(b) ${K_a} = C{\alpha ^2} = 0.2 \times {\left( {\frac{{3.2}}{{100}}} \right)^2} = 2.048 \times {10^{ – 4}}$.

Standard 11

Chemistry

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