$5.6$ liter of helium gas at $STP$ is adiabatically compressed to $0.7$ liter. Taking the initial temperature to be $T_1$, the work done in the process is
$5.6$ liter of helium gas at $STP$ is adiabatically compressed to $0.7$ liter. Taking the initial temperature to be $T_1$, the work done in the process is
- A
$\frac{9}{8}\,R{T_1}$
- B
$\frac{3}{2}\,R{T_1}$
- C
$\frac{15}{8}\,R{T_1}$
- D
$\frac{9}{2}\,R{T_1}$
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