14.Probability
easy

घटनाएँ $A$ और $B$ इस प्रकार हैं कि $P ( A )=0.42, P ( B )=0.48$ और $P ( A$ और $B )=0.16 .$ ज्ञात कीजिए

$P ( A$ या $B )$

A

$0.74$

B

$0.74$

C

$0.74$

D

$0.74$

Solution

It is given that $P ( A )=0.42$, $P ( B )=0.48$, $P ( A $ and $B )=0.16$

We know that $P ( A$ or $B )= P ( A )+ P ( B )- P ( A $ and $B )$

$P ( A$ or $B )=0.42+0.48-0.16=0.74$

Standard 11
Mathematics

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