14.Probability
easy

मान लें $A$ और $B$ स्वतंत्र घटनाएँ हैं तथा $P ( A )=0.3$ और $P ( B )=0.4 .$ तब $P ( A \cap B )$ ज्ञात कीजिए।

A

$0.12$

B

$0.12$

C

$0.12$

D

$0.12$

Solution

It is given that $P(A)=0.3$ and $P(B)=0.4$

If $\mathrm{A}$ and $\mathrm{B}$ are independent events, then

$P(A \cap B)=P(A) P(B)=0.3 \times 0.4=0.12$

Standard 11
Mathematics

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