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3-1.Vectors
easy
સદિશો $\vec A = (2,\, -\,3, \,1)$ અને $\vec B = (3,\, 4, \,n) $ પરસ્પર લંબ હોય, તો $n$ તેની કિંમત શોધો.
A$6$
B$4$
C$3$
D$2$
Solution
$\vec{A} \perp \vec{B}$
$\therefore \overrightarrow{ A } \cdot \overrightarrow{ B }=0$
$\therefore(2)(3)+(-3)(4)+(1)(n)=0$
$\therefore n=6$
$\therefore \overrightarrow{ A } \cdot \overrightarrow{ B }=0$
$\therefore(2)(3)+(-3)(4)+(1)(n)=0$
$\therefore n=6$
Standard 11
Physics
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