If x = {log _5}(1000) and y = {log _7}(2058) | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(a) $x = {\log _5}1000 = 3{\log _5}10 = 3 + 3{\log _5}2 = 3 + {\log _5}8$

$y = {\log _7}2058 = {\log _7}({7^3}.6) = 3 + {\log _7}6$

As ${\log _5

Vedclass · Accepted Answer

$x > y$

Vedclass · Answer

(a) $x = {\log _5}1000 = 3{\log _5}10 = 3 + 3{\log _5}2 = 3 + {\log _5}8$ $y = {\log _7}2058 = {\log _7}({7^3}.6) = 3 + {\log _7}6$ As ${\log _5}8 > {\log _5}5$ i.e., ${\log _5}8 > 1$. $x > 4$ And ${\log _7}6 < {\log _7}7$ i.e., ${\log _7}6 < 1$ $ herefore y < 4$; $ herefore x > y$.

If $x = {\log _5}(1000)$ and $y = {\log _7}(2058)$ then

Similar Questions

If ${\log _{0.3}}(x - 1) < {\log _{0.09}}(x - 1),$ then $x$ lies in the interval

The value of $\left(\left(\log _2 9\right)^2\right)^{\frac{1}{\log _2\left(\log _2 9\right)}} \times(\sqrt{7})^{\frac{1}{\log _4 7}}$ is. . . . . . .

If $3^x=4^{x-1}$, then $x=$

$(A)$ $\frac{2 \log _3 2}{2 \log _3 2-1}$ $(B)$ $\frac{2}{2-\log _2 3}$ $(C)$ $\frac{1}{1-\log _4 3}$ $(D)$ $\frac{2 \log _2 3}{2 \log _2 3-1}$

If $log_ab + log_bc + log_ca$ vanishes where $a, b$ and $c$ are positive reals different than unity then the value of $(log_ab)^3 + (log_bc)^3 + (log_ca)^3$ is

If ${a^2} + 4{b^2} = 12ab,$ then $\log (a + 2b)$ is