${a^{m{{\log }_a}n}} = $
${a^{m{{\log }_a}n}} = $
- A
${a^{mn}}$
- B
${m^n}$
- C
${n^m}$
- D
None of these
Similar Questions
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${{\sqrt {(5/2)} + \sqrt {(7 - 3\sqrt 5 )} } \over {\sqrt {(7/2)} + \sqrt {(16 - 5\sqrt 7 )} }}=$
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- [KVPY 2012]