argleft( {frac{{3 + i}}{{2 - i}} + frac{{3 - | vedclass

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Question

(c) $arg\left( {\frac{{3 + i}}{{2 - i}} + \frac{{3 - i}}{{2 + i}}} \right) = arg\left( {\frac{{6 + 5i + {i^2} + 6 - 5i + {i^2}}}{5}} \right)$
$ = arg

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(c) $arg\left( {\frac{{3 + i}}{{2 - i}} + \frac{{3 - i}}{{2 + i}}} \right) = arg\left( {\frac{{6 + 5i + {i^2} + 6 - 5i + {i^2}}}{5}} \right)$
$ = arg\left( {\frac{{10}}{5}} \right) = 0$.

$arg\left( {\frac{{3 + i}}{{2 - i}} + \frac{{3 - i}}{{2 + i}}} \right)$ is equal to

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