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7.Binomial Theorem
easy
${(\sqrt x - \sqrt y )^{17}}$ ના વિસ્તરણમાં $16^{th}$ મું પદ મેળવો.
A
$136x{y^7}$
B
$136xy$
C
$ - 136x{y^{15/2}}$
D
$ - 136x{y^2}$
Solution
(c) ${T_{16}} = {\,^{17}}{C_{15}}{(\sqrt x )^2}{( – \sqrt y )^{15}}$
$ = – \frac{{17 \times 16}}{{2 \times 1}} \times x{y^{15/2}} = – 136x{y^{15/2}}$
Standard 11
Mathematics
