7.Binomial Theorem
normal

$^n{C_0} - \frac{1}{2}{\,^n}{C_1} + \frac{1}{3}{\,^n}{C_2} - ...... + {( - 1)^n}\frac{{^n{C_n}}}{{n + 1}} = $

A

$n$

B

$1/n$

C

$\frac{1}{{n + 1}}$

D

$\frac{1}{{n - 1}}$

Solution

ट्रिक : $n =  1, 2$ रखने पर,

$n = 1$ पर $^1{C_0} – \frac{1}{2}{\,^1}{C_1} = 1 – \frac{1}{2} = \frac{1}{2}$

$n = 2$ पर $^2{C_0} – \frac{1}{2}\,{\,^2}{C_1} + \frac{1}{3}{\,^2}{C_2} = 1 – 1 + \frac{1}{3} = \frac{1}{3}$

जो विकल्प $(c)$ से प्राप्त होता हैं

Standard 11
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.