^n{C_0} - frac{1}{2}{,^n}{C_1} + frac{1}{3}{, | vedclass

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Question

(c) Trick : Put $n =  1, 2 $

At $n = 1,{\,^1}{C_0} - \frac{1}{2}{\,^1}{C_1} = 1 - \frac{1}{2} = \frac{1}{2}$

At $n = 2,\,{\,^2}{C_0} - \fra

Vedclass · Accepted Answer

$\frac{1}{{n + 1}}$

Vedclass · Answer

(c) Trick : Put $n =  1, 2 $

At $n = 1,{\,^1}{C_0} - \frac{1}{2}{\,^1}{C_1} = 1 - \frac{1}{2} = \frac{1}{2}$

At $n = 2,\,{\,^2}{C_0} - \frac{1}{2}\,{\,^2}{C_1} + \frac{1}{3}{\,^2}{C_2} = 1 - 1 + \frac{1}{3} = \frac{1}{3}$

which is given by option $(c)$.

$^n{C_0} - \frac{1}{2}{\,^n}{C_1} + \frac{1}{3}{\,^n}{C_2} - ...... + {( - 1)^n}\frac{{^n{C_n}}}{{n + 1}} = $

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